Ta có: \(\left|x-1\right|=2x+3\)
\(\Leftrightarrow\left[{}\begin{matrix}x-1=2x+3\left(x\ge1\right)\\1-x=2x+3\left(x< 1\right)\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}-x=4\\-3x=2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-4\left(loại\right)\\x=-\dfrac{2}{3}\left(nhận\right)\end{matrix}\right.\)