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Violympic toán 8
Các câu hỏi tương tự
Bài 4: Giải các phương trình sau
a) 4(x+5)(x+6)(x+10)(x+12)=\(3x^2\)
b) \(\frac{1}{x^2-3x+3}+\frac{2}{x^2-3x+4}=\frac{6}{x^2-3x+5}\)
c) \(\frac{4x}{4x^2-8x+7}+\frac{3x}{4x^2-10x+7}=1\)
d) \(\dfrac{2x}{2x^2-5x+3}+\dfrac{13x}{2x^2+x+3}=6\)
Tìm x, biết:
(4x-1)2-(3x+2)(3x-2)= (7x-1)(x+2)+(2x+1)2-(4x2+7)
(5x-1)(x+1)-2(x-3)2= (x+2)(3x-1)-(x+4)2+(x2-x)
(-x+5)(x-2)+(x-7)(x+7)= (3x+1)2-(3x-2)(3x+2)
(2x+3)2-(5x-4)(5x+4)= (x+5)2-(3x-1)(7x+2)-(x2-1)
(1-3x)2-(x-2)(9x+1)= (3x-4)(3x+4)-9(x+3)2
bài 1 giải phương trình
frac{3x+2}{3x-2}-frac{6}{2+3x}frac{9x^2}{9x^2-4}
frac{3}{5x-1}+frac{3}{3-5x}frac{4}{left(1-5xright)left(5x-3right)}
frac{3}{1-4x}frac{2}{4x+1}-frac{8+6x}{16x^2-1}
frac{5-x}{4x^2-8x}+frac{7}{8x}frac{x-1}{2xleft(x-2right)}+frac{1}{8x-16}
frac{x+1}{x^2+x+1}-frac{x-1}{x^2-x+1}frac{3}{xleft(x^4+x^2+1right)}
Đọc tiếp
bài 1 giải phương trình
\(\frac{3x+2}{3x-2}-\frac{6}{2+3x}=\frac{9x^2}{9x^2-4}\)
\(\frac{3}{5x-1}+\frac{3}{3-5x}=\frac{4}{\left(1-5x\right)\left(5x-3\right)}\)
\(\frac{3}{1-4x}=\frac{2}{4x+1}-\frac{8+6x}{16x^2-1}\)
\(\frac{5-x}{4x^2-8x}+\frac{7}{8x}=\frac{x-1}{2x\left(x-2\right)}+\frac{1}{8x-16}\)
\(\frac{x+1}{x^2+x+1}-\frac{x-1}{x^2-x+1}=\frac{3}{x\left(x^4+x^2+1\right)}\)
Phân tích các đa thức sau thành nhân tử :
a, x^2 + 4x + 3
b,16x - 5x^2 - 3
c, 2x^2 + 7x + 5
d, 2x^2 + 3x - 5
e,x^3 - 3x^2 + 1 - 3x
f, x^2 - 4x - 5
g, ( a^2 + 1 )^2 - 4a^2
h, x^3 - 3x^2 - 4x + 12
i, x^4 + x^3 + x + 1
k, x^4 - x^3 - x^2 + 1
l, ( 2x + 1 )^2 - ( x - 1 )^2
m,x^4 + 4x^2 - 5
Giải PT sau:a, 3x - 7 0b, 8 - 5x 0c, 3x - 2 5x + 8d, dfrac{3x-2}{3} dfrac{1-x}{2}e, ( 5x + 1)(x - 3) 0f, (x + 1)(2x - 3) 0g, 4x(x + 3) - 5(x + 3) 0h, 8(x - 6) - 2x(6 - x) 0i, dfrac{2}{x-1} + dfrac{1}{x} dfrac{2x+5}{x^2-x}k, dfrac{3}{x+2} - dfrac{2}{x-2} dfrac{2-x}{x^2-4}m, dfrac{3}{x} - dfrac{2}{x-3} dfrac{4-x}{x^2-3}n,dfrac{3}{2x+10}+ dfrac{2x}{x^2-25} dfrac{3}{x-5}u, dfrac{2}{x+3} - dfrac{3}{x-2} dfrac{x+4}{left(x+3right)left(x-2right)}
Đọc tiếp
Giải PT sau:
a, 3x - 7 = 0
b, 8 - 5x = 0
c, 3x - 2 = 5x + 8
d, \(\dfrac{3x-2}{3}\) = \(\dfrac{1-x}{2}\)
e, ( 5x + 1)(x - 3) = 0
f, (x + 1)(2x - 3) = 0
g, 4x(x + 3) - 5(x + 3) = 0
h, 8(x - 6) - 2x(6 - x) = 0
i, \(\dfrac{2}{x-1}\) + \(\dfrac{1}{x}\) = \(\dfrac{2x+5}{x^2-x}\)
k, \(\dfrac{3}{x+2}\) - \(\dfrac{2}{x-2}\) = \(\dfrac{2-x}{x^2-4}\)
m, \(\dfrac{3}{x}\) - \(\dfrac{2}{x-3}\) = \(\dfrac{4-x}{x^2-3}\)
n,\(\dfrac{3}{2x+10}\)+ \(\dfrac{2x}{x^2-25}\) = \(\dfrac{3}{x-5}\)
u, \(\dfrac{2}{x+3}\) - \(\dfrac{3}{x-2}\) = \(\dfrac{x+4}{\left(x+3\right)\left(x-2\right)}\)
Giải các phương trình sau:
1. \(a,\dfrac{6}{x-1}-\dfrac{4}{x-3}=\dfrac{8}{2x-6}\)
\(b,\dfrac{1}{x-2}+\dfrac{5}{x+1}=\dfrac{3}{2-x}\)
\(c,\dfrac{3x}{x-2}-\dfrac{x}{x-5}=\dfrac{3x}{\left(x-2\right)\left(5-x\right)}\)
2. \(a,\left(x+2\right)\left(3-4x\right)=x^2+4x+4\)
\(b,2x^2-6x+1\)
Giải các phương trình
a) \(\frac{3x+2}{2}-\frac{3x+1}{6}=\frac{5}{3}+2x\)
b) \(\frac{4x+3}{5}-\frac{6x-2}{7}=\frac{5x+4}{3}+3\)
c) \(\frac{x+4}{5}-x+4=\frac{x}{3}-\frac{x-2}{2}\)
d) \(\frac{5x+2}{6}-\frac{8x-1}{3}=\frac{4x+2}{5}-5\)
I : Phân tích đa thức thành nhân tử
1) x^4-3x^2-x+3
2) 3x+3y-x^2-2xy-y^2
3) x^4-x
4) x^2+5x+4
5) 4x^2+4x-8
6)x^2+x-42
7) 5x^2-3x-2
8) x^2-4x-1
9) x^2-7xy+12y^2
help me
1. giải phương trình
a, \(\frac{7x-3}{x-1}=\frac{2}{3}\)
b, \(\frac{2\left(3-7x\right)}{1+x}=\frac{1}{2}\)
c,\(\frac{5x-1}{3x+2}=\frac{5x-7}{3x-1}\)
d,\(\frac{4x+7}{x-1}=\frac{12x+5}{3x+4}\)