Ta có: |3x-2|=x+1(*)
Trường hợp 1: \(x\ge\frac{2}{3}\)
(*)\(\Leftrightarrow3x-2=x+1\)
\(\Leftrightarrow3x-2-x-1=0\)
\(\Leftrightarrow2x-3=0\)
\(\Leftrightarrow2x=3\)
hay \(x=\frac{3}{2}\)(tm)
*Trường hợp 2: \(x< \frac{2}{3}\)
(*)\(\Leftrightarrow2-3x=x+1\)
\(\Leftrightarrow2-3x-x-1=0\)
\(\Leftrightarrow-4x+1=0\)
\(\Leftrightarrow-4x=-1\)
hay \(x=\frac{1}{4}\)(tm)
Vậy: \(S=\left\{\frac{3}{2};\frac{1}{4}\right\}\)
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