Question

Giải phương trình:

\(\dfrac{3x-2}{3}\) - 2 = \(\dfrac{4x+1}{4}\)

Answer 1

Ta có: \(\dfrac{3x-2}{3}-2=\dfrac{4x+1}{4}\)

\(\Leftrightarrow\dfrac{4\left(3x-2\right)}{12}-\dfrac{24}{12}=\dfrac{3\left(4x+1\right)}{12}\)

\(\Leftrightarrow12x-8-24=12x+3\)

\(\Leftrightarrow12x-32-12x-3=0\)

\(\Leftrightarrow0x-35=0\)(vô lý)

Vậy: \(S=\varnothing\)

Answer 2

((3x - 2)/3) - 2 = (4x + 1)/4

⇔ (4(3x - 2)/12) - 24/12 = (3(4x + 1)/12)

⇔ 4(3x - 2) - 24 = 3(4x + 1)

⇔ 12x - 8 -24 = 12x + 3

⇔ -3 - 8 - 24 = 12x - 12x

⇔ -35 = 0x

⇒ Phương trình vô nghiệm.