\(\left\{{}\begin{matrix}2017-x=2017+y-2y\sqrt{2017}\\2017-y=2017+y-2x\sqrt{2017}\end{matrix}\right.\)
Trừ 2 vế ta có:
\(\Rightarrow y-x=y-x-2\sqrt{2017}\left(y-x\right)\)
\(\Rightarrow\left(y-x\right)\left(1-1+2\sqrt{2017}\right)=0\)
\(\Rightarrow x=y\)
thay vào hệ đầu