a) \(\left\{{}\begin{matrix}7x+5y=19\left(1\right)\\3x+5y=31\left(2\right)\end{matrix}\right.\)
Lấy (1) - (2) ta có pt : 4x = -12 => x = -3. Thay vào (1 ) => y =8
a) \(\left\{{}\begin{matrix}7x+5y=19\left(1\right)\\3x+5y=31\left(2\right)\end{matrix}\right.\)
Lấy (1) - (2) ta có pt : 4x = -12 => x = -3. Thay vào (1 ) => y =8
giải hệ pt sau
a\(\left\{{}\begin{matrix}4x+y=2\\8x+3y=5\end{matrix}\right.\) b\(\left\{{}\begin{matrix}3x_{ }-2y=11\\4x-5y=3\end{matrix}\right.\) c\(\left\{{}\begin{matrix}4x+3y=13\\5x-3y=_{ }-31\end{matrix}\right.\) D\(\left\{{}\begin{matrix}7X+5Y=19\\3x+5y=31\end{matrix}\right.\)
e\(\left\{{}\begin{matrix}7x-5y=3\\3x+10y=62\end{matrix}\right.\) f\(\left\{{}\begin{matrix}2x+5y=11\\3x+2y=11\end{matrix}\right.\) g\(\left\{{}\begin{matrix}x+3y=4y-x+5\\2x-y=3x-2\left(y+1\right)\end{matrix}\right.\)
giai hpt
a.\(\left\{{}\begin{matrix}x=y+4\\2x+3=0\end{matrix}\right.\)
b.\(\left\{{}\begin{matrix}2x+y=7\\3y-x=7\end{matrix}\right.\)
c.\(\left\{{}\begin{matrix}5x+y=3\\-x-\dfrac{1}{5}y=\dfrac{-3}{5}\end{matrix}\right.\)
d.\(\left\{{}\begin{matrix}3x-5y=-18\\x-5=2y\end{matrix}\right.\)
Giải các hệ phương trình sau bằng phương pháp thế:
a) \(\left\{{}\begin{matrix}x-y=3\\3x-4y=2\end{matrix}\right.\)
b) \(\left\{{}\begin{matrix}7x-3y=5\\4x+y=2\end{matrix}\right.\)
c) \(\left\{{}\begin{matrix}x+3y=-2\\5x-4y=11\end{matrix}\right.\)
Giải các hệ phương trình sau:
a, \(\left\{{}\begin{matrix}x+5y=-5\\3x+2y=11\end{matrix}\right.\)
\(b,\left\{{}\begin{matrix}4x+y=2\\8x+3y=5\end{matrix}\right.\)
giải hpt:
1, \(\left\{{}\begin{matrix}x^2+y^2+xy=3\\x^2+2xy=7x+5y-9\end{matrix}\right.\)
2, \(\left\{{}\begin{matrix}8x^3y^3+27=18y^3\\4x^2y+6x=y^2\end{matrix}\right.\)
giải hệ phương trình:
a)\(\left\{{}\begin{matrix}3xy=2\left(x+y\right)\\5yz=6\left(y-z\right)\\4xz=3\left(x+y\right)\end{matrix}\right.\)
b)\(\left\{{}\begin{matrix}\dfrac{x}{4}=\dfrac{y}{3}=\dfrac{z}{9}\\7x-3y+2z=37\end{matrix}\right.\)
Giải hệ phương trình sau
a. \(\left\{{}\begin{matrix}x^2+y^2+2\left(x+y\right)=23\\x+y+xy=11\end{matrix}\right.\)
b. \(\left\{{}\begin{matrix}x^2+4x+y=0\\\left(x+2\right)^2+5y=16\end{matrix}\right.\)
c. \(\left\{{}\begin{matrix}x+y+\frac{1}{x}+\frac{1}{y}=5\\x^2+y^2+\frac{1}{x^2}+\frac{1}{y^2}=9\end{matrix}\right.\)
Giải các hệ phương trình:
a) \(\left\{{}\begin{matrix}\left(x+3\right)\left(y-5\right)=xy\\\left(x-2\right)\left(y+5\right)=xy\end{matrix}\right.\)
b) \(\left\{{}\begin{matrix}\dfrac{1}{x}+\dfrac{1}{y}=\dfrac{3}{4}\\\dfrac{1}{6x}+\dfrac{1}{5y}=\dfrac{2}{15}\end{matrix}\right.\)
Giải hệ phương trình sau :
a, \(\left\{{}\begin{matrix}\left(x^2+1\right)\left(y^2+1\right)=10\\\left(x+y\right)\left(xy-1\right)=3\end{matrix}\right.\)
b, \(\left\{{}\begin{matrix}x^3-1=2y\\y^3-1=2x\end{matrix}\right.\)
c, \(\left\{{}\begin{matrix}2x^2+xy=3x\\2y^2+xy=3y\end{matrix}\right.\)