Question

giải bất phương trình :

\(|x-3|\) > x - 6

Help me

Answer 1

|x-3| >x-6

\(\left[{}\begin{matrix}\left\{{}\begin{matrix}x-3\ge0\\x-3>x-6\end{matrix}\right.\\\left\{{}\begin{matrix}x-3< 0\\-x+3>x-6\end{matrix}\right.\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x\ge3\\-3>6\end{matrix}\right.\\\left\{{}\begin{matrix}x< 3\\2x< 9\end{matrix}\right.\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x\ge3\\x< 3\end{matrix}\right.\)\(\Rightarrow dung\forall x\)