Question

giải bật phương trình sau 

b) \(\dfrac{3x+1}{2}\le1+\dfrac{x+2}{3}\)

 

Answer 1

`b)(3x+1)/2<=1+(x+2)/3`

`<=>3(3x+1)<=6+2(x+2)`

`<=>9x+3<=2x+10`

`<=>9x-2x<=10-3`

`<=>7x<=7`

`<=>x<=1`

Vậy BPT có tập nghiệm `S={x|x<=1}`

Answer 2

\(\dfrac{3x+1}{2}\le1+\dfrac{x+2}{3}\)

\(\Leftrightarrow\dfrac{3\left(3x+1\right)}{6}\le\dfrac{6+2\left(x+2\right)}{6}\)

\(\Rightarrow9x+3\le6+2x+4\)

\(\Leftrightarrow7x\le7\)

\(\Leftrightarrow x\le1\)

Vậy...

Answer 3

Answer 4

BPT \(\Leftrightarrow\dfrac{3x+1}{2}\le\dfrac{x+5}{3}\) 

\(\Leftrightarrow9x+3\le2x+10\) \(\Leftrightarrow7x\le7\) \(\Leftrightarrow x\le1\)

  Vậy ...

Answer 5