Question

Giá trị của x thỏa mãn :x²-3-x(x+6)=0

Answer 1

Nhân hết ra!

Answer 2

giúp mình nhé

Answer 3

\(x^2-3-x\left(x+6\right)=0\)

\(x^2-3-x^2-6x=0\)\(\left(x^2-x^2\right)-3-6x=0\)

\(-3-6x=0\)\(\Rightarrow-6x=3\Rightarrow x=\dfrac{-1}{2}\)

Answer 4

\(x^2-3-x\left(x+6\right)=0\)

\(\Leftrightarrow x^2-3-x^2-6x=0\)

\(\Leftrightarrow-6x=3\)

\(\Leftrightarrow x=-\dfrac{1}{2}\)

Vậy \(x=-\dfrac{1}{2}\)

Answer 5

\(x^2-2-x\left(x+6\right)=0\)

\(x^2-3-x^2-6x=0\)

\(-6x-3=0\)

\(\Rightarrow x=\dfrac{1}{2}\)

Vậy \(x=\dfrac{1}{2}\)