\(\dfrac{15-x}{7}=\dfrac{x+7}{4}\Leftrightarrow4\left(15-x\right)=7\left(x+7\right)\)
\(\Rightarrow60-4x=7x+49\)
\(\Rightarrow60-49=7x+4x\)
\(\Rightarrow11=11x\)
\(\Rightarrow x=1\)
Áp dụng tính chất dãy tỉ số bằng nhau, ta có:
\(\dfrac{15-x}{7}=\dfrac{x+7}{4}=\dfrac{15-x+x+7}{7+4}=\dfrac{22}{11}=2\)
\(\Rightarrow\dfrac{15-x}{7}=2\Rightarrow15-x=14\Rightarrow x=1\)
Vậy \(x=1\).