a) \(x^2+4x+4-x^2+6x-9=10x-5\)
b) \(\left(x+3\right)\left(x-1\right)+\left(5-x\right)^2=x^2+2x-3+x^2-10x+25=2x^2-8x^2+22\)
a) \(\left(x+2\right)^2-\left(x-3\right)^2=0\)
\(\Leftrightarrow\left(x+2-x+3\right)\left(x+2+x-3\right)=0\)
\(\Leftrightarrow2x-1=0\)
\(\Leftrightarrow x=\dfrac{1}{2}\)
b) \(\left(x+3\right)\left(x-1\right)=\left(5-x\right)^2\)
\(\Leftrightarrow x^2+2x-3=x^2-10x+25\)
\(\Leftrightarrow12x-28=0\)
\(\Leftrightarrow x=\dfrac{7}{3}\)
ghi đề chả rõ ghì hết
thấy cây b tưởng giải pt