ĐKXĐ: \(x\ge\frac{3}{2}\)
\(\Leftrightarrow\sqrt{2x+1}-\sqrt{x+3}+\sqrt{2x-3}-\sqrt{x-1}=0\)
\(\Leftrightarrow\frac{x-2}{\sqrt{2x+1}+\sqrt{x+3}}+\frac{x-2}{\sqrt{2x-3}+\sqrt{x-1}}=0\)
\(\Leftrightarrow\left(x-2\right)\left(\frac{1}{\sqrt{2x+1}+\sqrt{x+3}}+\frac{1}{\sqrt{2x-3}+\sqrt{x-1}}\right)=0\)
\(\Leftrightarrow x-2=0\Rightarrow x=2\)