Question

Đưa biểu thức sau về dạng bình phương 

3 - \(\sqrt{8}\)

Answer 1

\(3-\sqrt{8}=3-2\sqrt{2}=\left(\sqrt{2}\right)^2-2.\sqrt{2}.1+1^2=\left(\sqrt{2}-1\right)^2\)

Answer 2

3 - \(\sqrt{8}\)

= 3 - 2\(\sqrt{2}\)

= 1 - 2\(\sqrt{2}\) + 2

= \(\left(1-\sqrt{2}\right)^2\)

Answer 3

\(3-\sqrt{8}=\left(\sqrt{2}-1\right)^2\)