`<=> 9/2 . 2^x = 9 . 2^5`
`<=> 9 . 2^(x-1) = 9 . 2^5`
`-> x-1 = 5`
`-> x = 6`
\(2x.\left(\dfrac{1}{2}+4\right)=9.32\\ 2x.\dfrac{9}{2}=288\\ 9x=288\\ x=288:9\\ x=32\)
`<=> 9/2 . 2^x = 9 . 2^5`
`<=> 9 . 2^(x-1) = 9 . 2^5`
`-> x-1 = 5`
`-> x = 6`
\(2x.\left(\dfrac{1}{2}+4\right)=9.32\\ 2x.\dfrac{9}{2}=288\\ 9x=288\\ x=288:9\\ x=32\)
Tìm x,y,z biết :
1) \(\dfrac{x}{5}=\dfrac{y}{4}\)và x2 - y2=4
2) \(\dfrac{2x+1}{5}=\dfrac{3y-2}{7}=\dfrac{2x+3y-1}{6x}\)
3) \(\dfrac{x-1}{2}=\dfrac{y-2}{3}=\dfrac{z-3}{4}\)và 2x + 3y - z = 95
1. tìm x
a, 2x - \(\dfrac{1}{2}\) : \(\dfrac{3}{4}\) = \(\dfrac{12}{9}\)
b, x\(^2\) - 2 = 0
2. Cho
A = \(\dfrac{1,11+0,19-13.2}{2,06+0,54}\) - \(\left(\dfrac{1}{2}+\dfrac{1}{4}\right)\) : 2
B = \(\left(5\dfrac{7}{8}-2\dfrac{1}{4}-0,5\right)\) : \(2\dfrac{23}{26}\)
a, Rút gọn A, B
b, Tìm x ϵ Z để A < x < B
1)Tìm x, biết:
a)\(\dfrac{x-1}{3}=\dfrac{x+1}{5}\)
b)\(\dfrac{2x+1}{3x-2}=\dfrac{5x+1}{9x+1}\)
2)Tìm x,y,z biết:
a)\(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z+1}{4}\) và 2x+3y-z=11
b)\(\dfrac{2x+1}{5}=\dfrac{3y-2}{7}=\dfrac{2x+3y-1}{6x}\)
Giúp mình với mình đang cần gấp!!!THANK NHÌU
Tìm giá trị lớn nhất của biểu thức:
a) C = 20013 - \(\left|5-2x\right|\)
b) D = 7 - \(\left|\dfrac{2}{3}+\dfrac{1}{4}x\right|\)
c) N = 1 + \(\dfrac{1}{\left|2x-1\right|}\)
d) E = 13 - ( 2x - \(\dfrac{1}{3}\) )2
e) F = -( 3x + \(\dfrac{1}{2}\) )4 + 2015
g) G = \(\dfrac{2x^2+15}{x^2+3}\)
\(^{\dfrac{-7}{1+2x}}=\dfrac{5}{2-3x}\)
Tìm x:
\(\dfrac{2}{3}-\dfrac{1}{3}.\left(x-\dfrac{3}{2}\right)-\dfrac{1}{2}.\left(2x+1\right)=5\)
1. tìm x biết
a, (2x - 3)\(^2\) = |3 - 2x|
b, (x - 1)\(^2\) + (2x - 1)\(^2\) = 0
c, 5 - x\(^2\) = 1
d, x - 2\(\sqrt{x}\) = 0
g, (x - 1) + \(\dfrac{1}{7}\) = 0
\(\dfrac{x-1}{2}=\dfrac{y-2}{3}=\dfrac{z-3}{4}\) và 2x + 3y - z = 50
Thu gọn các đơn thức đồng dạng trong đa thức sau:
a) \(A=x^5-\dfrac{1}{2}x+7x^3-2x+\dfrac{1}{5}x^3+3x^4-x^5+\dfrac{2}{5}x^4+15\)
b) \(B=3x^2-10+\dfrac{2}{5}x^3+7x-x^2+8+7x^2\)
c) \(C=\dfrac{1}{7}x-2x^4+5x+6\)
\(\dfrac{2^{18}}{32^3}.\dfrac{27^4}{54^3}\) \(\dfrac{x+1}{9}=\dfrac{4}{x+1}\) Tìm x, y biết:
\(\dfrac{40^4}{120^4}:\dfrac{130^3}{390^3}\) \(19.5^{2x+7}=475\) 5x=4y và y-x=7
\(2^x.8\) \(\dfrac{2x}{5}=\dfrac{10}{x}\)
\((\dfrac{1}{2})^x=\dfrac{1}{32}\) \(33^x:11^x=243\)