Question

\(\dfrac {2x+3}{7}=\dfrac {4x-1}{15}\)

Answer 1

\(\frac{2x+3}{7}=\frac{4x-1}{15}\)

=> \(\frac{15\left(2x+3\right)}{105}=\frac{7\left(4x-1\right)}{105}\)

=> \(15\left(2x+3\right)=7\left(4x-1\right)\)

=> \(30x+45=28x-7\)

=>\(28x-30x=45+7\)

=> \(-2x=52\)

=>\(x=52:-2\)

=> \(x=-26\)

Answer 2

https://i.imgur.com/vaFYiQC.jpg

Answer 3

\(\frac{2x+3}{7}=\frac{4x-1}{15}\)

=> \(\left(2x+3\right).15=\left(4x-1\right).7\)

=> 30x +45 = 28x - 7

=> 30x - 28x = -7 - 45

=> 2x = -52

x = -52 : 2

x= -26

Answer 4

\(\frac{2x+3}{7}=\frac{4x-1}{15}\)

=> (2x + 3) .15 = (4x - 1) .7

=> 30x + 45 = 28x - 7

=> 30x - 28x = (-7) - 45

=> 30x - 28x = -52

=> 2x = -52

x = (-52) : 2

x = -26.

Vậy x = -26.

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