Question

Chứng minh rằng: Nếu \(\dfrac{x}{y}\)=\(\dfrac{z}{t}\) thì \(\left(\dfrac{x-y}{z-t}\right)^{1996}=\dfrac{x^{1996}+y^{1996}}{z^{1996}+x^{1996}}\) với các điều kiện các mẫu đều khác 0

Giúp mk vs ạ!

Answer 1

\(\dfrac{x}{y}=\dfrac{z}{t}\\ \Rightarrow\dfrac{x}{z}=\dfrac{y}{t}\\ \Rightarrow\dfrac{x}{z}=\dfrac{y}{t}=\dfrac{x-y}{z-t}\\ \Rightarrow\dfrac{x^{1996}}{z^{1996}}=\dfrac{y^{1996}}{t^{1996}}=\left(\dfrac{x-y}{z-t}\right)^{1996}\\ \dfrac{x^{1996}}{z^{1996}}=\dfrac{y^{1996}}{t^{1996}}=\dfrac{x^{1996}+y^{1996}}{z^{1996}+t^{1996}}\\ \Rightarrow\left(\dfrac{x-y}{z-t}\right)^{1996}=\dfrac{x^{1996}+y^{1996}}{z^{1996}+t^{1996}}\)