\(\Delta'=\left[-\left(m+1\right)\right]^2-\left(2m^2+m+3\right)\)
\(\Delta'=-m^2+m-2\left(1\right)\)
\(\Delta< 0\forall m\) bởi vì:
\(\left\{{}\begin{matrix}a_{\left(1\right)}< 0\\\Delta_{\left(1\right)}< 0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}-1< 0\left(đúng\right)\\1^2-4\left(-1\right)\left(-2\right)< 0\left(đúng\right)\end{matrix}\right.\)