Ta có :
\(\frac{x^6+1}{x^3}=\frac{6}{x^3}+\frac{1}{x^3}=\frac{x^3+1}{x^3}\)
\(\rightarrow f\left(x\right)=x^3+\left(\frac{1}{x}\right)^3\)
Lại có :
\(f\left(\frac{1}{x}\right)=x^3+\left(\frac{1}{x}\right)^3=x^3+\frac{1}{x^3}\)
\(\rightarrow f\left(\frac{1}{x}\right)=f\left(x\right)=\left(x^3+\frac{1}{x^3}\right)\)