a) sai đề.
Sửa:\(\frac{x}{y}+\frac{y}{x}\ge2\)
Áp dụng BĐT AM-GM ta có:
\(\frac{x}{y}+\frac{y}{x}\ge2.\sqrt{\frac{x}{y}.\frac{y}{x}}=2\)
Dấu " = " xảy ra <=> x=y
b) \(\left(x+y+2\right)\left(\frac{1}{x}+\frac{1}{y}+\frac{1}{2}\right)\ge9\)
Áp dụng BĐT AM-GM ta có:
\(\left(x+y+2\right)\left(\frac{1}{x}+\frac{1}{y}+\frac{1}{2}\right)\ge3.\sqrt[3]{2xy}.\frac{3}{\sqrt[3]{2xy}}=9\)
Dấu " = " xảy ra <=> x=y=2