\(x\ge2y\Rightarrow\frac{x}{y}\ge2\)
Đặt \(\frac{x}{y}=a\Rightarrow a\ge2\)
\(M=\frac{x}{y}+\frac{y}{x}=a+\frac{1}{a}=\frac{a}{4}+\frac{1}{a}+\frac{3a}{4}\ge2\sqrt{\frac{a}{4a}}+\frac{3.2}{4}=\frac{5}{2}\)
\(M_{min}=\frac{5}{2}\) khi \(a=2\) hay \(x=2y\)