Ta có:\(\frac{a}{3}=\frac{b}{4}=\frac{c}{5}\) và a+2b+3c=44,2
\(\Rightarrow\frac{a}{3}=\frac{b}{4}=\frac{c}{5}=\frac{a+2b+3c}{3+4\cdot2+5\cdot3}=\frac{44,2}{26}=\frac{17}{10}=1,7\)(T/C...)
\(\Rightarrow a=1,7\cdot3=5,1;b=4\cdot1,7=6,8;c=5\cdot1,7=8,5\)
\(\Rightarrow a+b-c=5,1+6,8-8,5=3,4\)