a: BC=10cm
Xét ΔABC có AD là phân giác
nên BD/AB=CD/AC
=>BD/3=CD/4=10/7
=>BD=30/7cm; CD=40/7cm
c: \(AD=\dfrac{2\cdot AB\cdot AC}{AB+AC}\cdot cos45^0\)
\(\Leftrightarrow AD=\sqrt{2}\cdot\dfrac{AB\cdot AC}{AB+AC}\)
=>\(\dfrac{\sqrt{2}}{AD}=\dfrac{1}{AB}+\dfrac{1}{AC}\)