Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\dfrac{a}{b}=\dfrac{b}{c}=\dfrac{c}{d}=\dfrac{a+b+c}{b+c+d}\) (với \(b+c+d\ne0\))
Đặt: \(\dfrac{a}{b}=\dfrac{b}{c}=\dfrac{c}{d}=\dfrac{a+b+c}{b+c+d}=t\)
Ta có:
\(\left\{{}\begin{matrix}\dfrac{a}{b}.\dfrac{b}{c}.\dfrac{c}{d}=t.t.t=\dfrac{a}{d}=t^3\\\left(\dfrac{a+b+c}{b+c+d}\right)^3=t^3\end{matrix}\right.\Rightarrowđpcm\)
Bài 1:
a) Cho a(y+z) = b(z+c) = c(x+y) Tính: \(\dfrac{y-z}{a\left(b-c\right)}=\dfrac{z-c}{b\left(c-a\right)}=\dfrac{x-y}{c\left(a-b\right)}\)
b) \(Cho\dfrac{a}{2014}=\dfrac{b}{2015}=\dfrac{c}{2016}cm:4\left(a-b\right)\left(b-c\right)=\left(c-a\right)^2\)
c) \(\dfrac{a}{a'}+\dfrac{b'}{b}=1\) và \(\dfrac{b}{b'}+\dfrac{c'}{c}=1\)
cm: abc+a'b'c'=0
bài 4:
a) \(\dfrac{3x-y}{x+y}=\dfrac{3}{4}\) Tính: \(\dfrac{x}{y}\)
b) \(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{4}\) Tính P = \(\dfrac{xy+yz+xz}{x^2+y^2-z^2}\)
c) \(\dfrac{a}{b+c+d}=\dfrac{b}{a+c+d}=\dfrac{c}{a+b+d}=\dfrac{d}{a+b+c}\)
Tính : P = \(\dfrac{a+b}{c+d}+\dfrac{c+b}{a+d}=\dfrac{c+d}{a+b}=\dfrac{a+d}{c+b}\)
d) \(\dfrac{a+b}{c}=\dfrac{b+c}{a}=\dfrac{c+a}{b}\) Tính: \(P=\left(1+\dfrac{a}{b}\right)\left(1+\dfrac{b}{c}\right)\left(1+\dfrac{c}{a}\right)\)
Cho tỉ lệ thức \(\dfrac{a}{b}=\dfrac{c}{d}\)
Chứng minh rằng \(\dfrac{a}{a-b}=\dfrac{c}{c-d}\)
bằng 3 các(giả thiết a khác b;c khác d và mỗi số a,b,c,d khác 0)
Cho tỉ lệ thức \(\dfrac{a}{b}=\dfrac{c}{d}\)chứng tỏ:
a)\(\dfrac{a}{a-b}=\dfrac{c}{c-d}\) b)\(\dfrac{a^n-b^n}{c^n-d^n}=\dfrac{\left(a-b\right)^n}{\left(c-d\right)^n}\) c)\(\dfrac{a}{3\text{a}+b}=\dfrac{c}{3c+d}\)
Cho; \(\dfrac{a}{2b}=\dfrac{b}{2c}=\dfrac{c}{2d}=\dfrac{d}{2a}\left(a,b,c,d>0\right)\)
Tính \(A=\dfrac{2011a-2010b}{c+d}+\dfrac{2011b-2010c}{a+d}+\dfrac{2011c-2010a}{a+b}+\dfrac{2011d-2010a}{b+c}\)
\(\dfrac{a}{b}=\dfrac{b}{c}=\dfrac{c}{d}.CMR\left(\dfrac{a+b+c}{b+c+d}\right)^3=\dfrac{a}{d}\)
Cho biểu thức\(\dfrac{a}{b}=\dfrac{c}{d}\). C/M biểu thức\(\left(\dfrac{a+b}{c+d}\right)^3=\dfrac{a^3+b^3}{c^3+d^3}\)
Cho a,b,c,d là 4 số khác 0; biết \(\dfrac{a}{b}=\dfrac{c}{d}\).Chứng minh rằng \(\dfrac{a^{2017}+b^{2017}}{c^{2017}+d^{2017}}=\dfrac{\left(a-b\right)^{2017}}{\left(c-d\right)^{2017}}\)
cho \(\dfrac{a}{b}=\dfrac{b}{c}=\dfrac{c}{d}\) chứng minh \(\left(\dfrac{a+b+c}{b+c+d}\right)^3=\dfrac{a}{d}\)
a) Cho \(\dfrac{a}{b}=\dfrac{c}{d}\) (\(a,b,c,d\ne0\)). Chứng minh rằng:
1) \(\dfrac{2a+5b}{3a-4b}=\dfrac{2c+5d}{3c-4d}\)
2) \(\dfrac{ab}{cd}=\dfrac{a^2+b^2}{c^2+d^2}\)
3) \(\dfrac{a^3+b^3}{c^3+d^3}=\dfrac{\left(a+b\right)^3}{\left(c+d\right)^3}\) \(\left(\dfrac{a}{b}=\dfrac{c}{d}\ne1\right)\)
b)Cho \(\dfrac{2a+13b}{3a-7b}=\dfrac{2c+13d}{3c-7d}\). Chứng minh rằng:\(\dfrac{a}{b}=\dfrac{c}{d}\)
c)Cho \(\dfrac{cy-bz}{x}=\dfrac{az-cx}{y}=\dfrac{bx-ay}{z}\). Chứng minh rằng: \(\dfrac{a}{x}=\dfrac{b}{y}=\dfrac{c}{z}\)
