Đặt :
\(\dfrac{a}{2}=\dfrac{b}{4}=\dfrac{c}{7}=k\) \(\Leftrightarrow\left\{{}\begin{matrix}a=2k\\b=4k\\c=7k\end{matrix}\right.\) \(\left(1\right)\)
Thay \(\left(1\right)\) zô \(A=\dfrac{a-b+c}{a+2b-c}\) ta được :
\(A=\dfrac{2k-5k+7k}{2k+2.5k-7k}\)\(=\dfrac{4k}{5k}\) \(=\dfrac{4}{5}\)