Đặt vế trái là P
\(P=\frac{b+c+1}{a+5}+1+\frac{c+a+4}{b+2}+1+\frac{a+b+3}{c+3}+1-3\)
\(P=\frac{a+b+c+6}{a+5}+\frac{a+b+c+6}{b+2}+\frac{a+b+c+6}{c+3}-3\)
\(P=\frac{12}{a+5}+\frac{12}{b+2}+\frac{12}{c+3}-3\)
\(P\ge\frac{12.9}{a+b+c+10}-3=\frac{12.9}{6+10}-3=\frac{15}{4}\)
Dấu "=" xảy ra khi \(\left\{{}\begin{matrix}a=\frac{1}{3}\\b=\frac{10}{3}\\c=\frac{7}{3}\end{matrix}\right.\)
Đề bài sai :)