a: Khi x=1 thì \(A=\dfrac{1+1}{2}=1\)
b: Để A=2 thì x+1=4
=>x=3
c: \(B=\dfrac{2+x-2+x}{x\left(x-2\right)}=\dfrac{2x}{x\left(x-2\right)}=\dfrac{2}{x-2}\)
d: C=A*B=2/(x-2)*x+1/2=x+1/x-2
Để C la số nguyên thì x-2+3 chia hết cho x-2
=>\(x-2\in\left\{1;-1;3;-3\right\}\)
hay \(x\in\left\{3;5;-1;1\right\}\)