a) ĐKXĐ: x ≠ -1
\(A=\dfrac{3\left(x+1\right)}{x^2\left(x+1\right)+\left(x+1\right)}=\dfrac{3\left(x+1\right)}{\left(x^2+1\right)\left(x+1\right)}=\dfrac{3}{x^2+1}\)
b) Vì x2 ≥ 0 ∀ x ≠ -1
=> x2 + 1 ≥ 1
=> \(\dfrac{3}{x^2+1}\le3\)
=> A ≤ 3
Dấu "=" xảy ra <=> x = 0