\(A=1.2+2.3+...+18.19\)
\(3A=1.2\left(3-0\right)+2.3\left(4-1\right)+...+18.19\left(20-17\right)\)
\(3A=1.2.3-0.1.2+2.3.4-1.2.3+...+18.19.20-17.18.19\)
\(3A=18.19.20=6840\)
\(\Rightarrow A=\dfrac{6840}{3}=2280\)
\(A=1.2+2.3+...+18.19\)
\(3A=1.2\left(3-0\right)+2.3\left(4-1\right)+...+18.19\left(20-17\right)\)
\(3A=1.2.3-0.1.2+2.3.4-1.2.3+...+18.19.20-17.18.19\)
\(3A=18.19.20=6840\)
\(\Rightarrow A=\dfrac{6840}{3}=2280\)
Tính A = 1.2 + 2.3 + 3.4 + … + n.(n + 1)
Tính A = 1.2 + 2.3 + 3.4 + … + n.(n + 1)
Tính A = [1 + (1 + 2) + (1 + 2 + 3) + ..... + (1 + 2 + 3 + ..... + 98)]/(1.2 + 2.3 + 3.4 + ..... + 98.99)
CMR : a) 1/2! + 2/3! + 3/4! +...+ 99/100! < 1
b) 1.2-1/2! + 2.3-1/3! + 3.4-1/4! +...+ 99.100-1/100! < 2
Chứng minh: \(1.2+2.3+3.4+......+n\left(n+1\right)⋮3\)
Tính tổng A=\(\dfrac{1}{1.2}\)+\(\dfrac{1}{2.3}\)+\(\dfrac{1}{3.4}\)+...+\(\dfrac{1}{49.50}\)
tính Q
Q=\(\frac{1.98+2.97+3.96+...+2.97+1.98}{1.2+2.3+3.4+...+96.97+97.98+98.99}\)
cho A= \(\frac{1}{1.2^2}+\frac{1}{2.3^2}+\frac{1}{3.4^2}+...+\frac{1}{49.50^2}\)
B= \(\frac{1}{2^{ }}+\frac{1}{3^2}+\frac{1}{4^2}+...+\frac{1}{50^2}\)
Chứng minh : A < \(\frac{1}{2}\)<B
Cho \(M=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{99.100}\)
\(N=\frac{2016}{51}+\frac{2016}{52}+...+\frac{2016}{100}\)
CMR N chia hết cho M.