Đại số lớp 7
Các câu hỏi tương tự
chứng minh rằng:
\(\frac{1.2-1}{2!}+\frac{2.3-1}{3!}+\frac{3.4-1}{4!}+...+\frac{99.100-1}{100!}< 2\)
mình ngu toán chúng minh (hép mi)
cho A = \(\frac{1}{1.2}+\frac{1}{3.4}+...+\frac{1}{99.100}\)
CMR \(\frac{7}{12}< A< \frac{5}{6}\)
Cho :
A = \(\left(\frac{1}{2}_{ }+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+.....+\frac{1}{2016}+\frac{1}{2017}\right)\)
B = \(\left(\frac{2016}{1}+\frac{2015}{2}+\frac{2014}{3}+....+\frac{1}{2014}+\frac{1}{2015}+\frac{1}{2016}\right)\)
Tính \(\frac{B}{A}\) ?
[Các bạn giúp mình với !!!]
Thực hiện phép tính:
\(\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2016}+\frac{1}{2017}}{\frac{2016}{1}+\frac{2015}{2}+\frac{2014}{3}+...+\frac{2}{2015}+\frac{1}{2016}}\)
CMR:\(\frac{3}{\left(1.2\right)^2}+\frac{5}{\left(2.3\right)^2}+\frac{7}{\left(3.4\right)^2}+...+\frac{19}{\left(9.10\right)^2}< 1\)
Tính
\(\left(1-\frac{2}{2.3}\right)\left(1-\frac{2}{3.4}\right)\left(1-\frac{2}{4.5}\right)...\left(1-\frac{2}{99.100}\right)\)
Tìm x biết: \(\left|x+\frac{1}{1.2}\right|+\left|x+\frac{1}{1.3}\right|+\left|x+\frac{1}{3.4}\right|+...+\left|x+\frac{1}{99.100}\right|=100x\)
cho A= \(\frac{1}{1.2^2}+\frac{1}{2.3^2}+\frac{1}{3.4^2}+...+\frac{1}{49.50^2}\)
B= \(\frac{1}{2^{ }}+\frac{1}{3^2}+\frac{1}{4^2}+...+\frac{1}{50^2}\)
Chứng minh : A < \(\frac{1}{2}\)<B
Rút gọn:
a/ \(A=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{2009.2000}\)
b/ \(B=\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+...+\frac{1}{1998.1999.2000}\)
c/ \(C=\frac{1}{2.4}+\frac{1}{4.6}+\frac{1}{6.8}+...+\frac{1}{2006.2008}\)