\(\frac{a}{b}< \frac{a+2019}{b+2019}\Leftrightarrow a\left(b+2019\right)< b\left(a+2019\right)\)
\(\Leftrightarrow ab+2019a< ab+2019b\)
\(\Leftrightarrow2019a< 2019b\)
\(\Leftrightarrow a< b\) (luôn đúng theo giả thiết)
Vậy \(\frac{a}{b}< \frac{a+2019}{b+2019}\)