=3/2*7/3+4/3*1/2
=21/6+4/6=25/6
\(\dfrac{11}{2}.\dfrac{21}{3}+\dfrac{11}{3}.\dfrac{1}{2}\)
\(=\dfrac{77}{2}+\dfrac{11}{6}=\dfrac{121}{3}\)
Đáp án đúng đây cậu:v.
\(1\dfrac{1}{2}\cdot2\dfrac{1}{3}+1\dfrac{1}{3}\cdot\dfrac{1}{2}=\dfrac{3}{2}\cdot\dfrac{7}{3}+\dfrac{4}{3}\cdot\dfrac{1}{2}=\dfrac{21}{6}+\dfrac{4}{6}=\dfrac{25}{6}\)