\(\dfrac{x+1}{x}=-4\Leftrightarrow-4x=x+1\Leftrightarrow x=-\dfrac{1}{5}\\ \dfrac{x^2+1}{x^2}=\dfrac{\dfrac{1}{25}+1}{\dfrac{1}{25}}=\dfrac{26}{25}\cdot25=26\)
\(x^2+\dfrac{1}{x^2}=\left(x^2+2+\dfrac{1}{x^2}\right)^2-2=\left(x+\dfrac{1}{x}\right)^2-2=\left(-4\right)^2-2=14\)