Question

Bài 1. Phân tích các đa thức sau thành nhân tử:

a) 4a - 4b.

b) 2x² - 4xy + 2y².

c) x² - y² + 3x + 3y.

d) x⁴ - 27x.

Giúp mình với mình cần gấp lắm lắm

Answer 1

`a)`\(4a-4b=4\left(a-b\right)\)

`b)`\(2x^2-4xy+2y^2=2\left(x^2-2xy+y^2\right)=2\left(x-y\right)^2\)

`c)`\(x^2-y^2+3x+3y=\left(x-y\right)\left(x+y\right)+3\left(x+y\right)=\left(x+y\right)\left(x-y+3\right)\)

`d)`\(x^4-27x=x\left(x^3-27\right)=x\left(x-3\right)\left(x^2+3x+9\right)\)

Answer 2

\(a,4a-4b\\ =4.\left(a-b\right)\\ b,2x^2-4xy+2y^2=2.\left(x^2-2xy+y^2\right)\\ =2.\left(x-y\right)^2\\ c,x^2-y^2+3x+3y\\ =\left(x-y\right).\left(x+y\right)+3.\left(x+y\right)\\ =\left(x+y\right).\left(x-y+3\right)\\ d,x^4-27x\\ =x.\left(x^3-27\right)=x.\left(x-3\right).\left(x^2+3x+9\right)\)