\(-x^2+5=\left(\sqrt{5}-x\right)\left(\sqrt{5}+x\right)\)
\(-x^2-4x-4=-\left(x^2+4x+4\right)=-\left(x+2\right)^2\)
\(x^8-1=\left(x^4-1\right)\left(x^4+1\right)=\left(x^2-1\right)\left(x^2+1\right)\left(x^4+1\right)\)
\(=\left(x-1\right)\left(x+1\right)\left(x^2+1\right)\left(x^4+1\right)\)
Câu 2:
a: Đề thiếu vế phải nha bạn
b: =>(x-căn 7)^2=0
=>x-căn 7=0
=>x=căn 7