a) \(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{5}\)và \(2x-y+3z=28\)
Theo tính chất dãy tỉ số bằng nhau ta có
\(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{x}{5}=\dfrac{2x-y+3z}{4-3+15}=\dfrac{28}{16}=1,75\)
\(\Rightarrow\dfrac{x}{2}=1,75\Rightarrow x=3,5\)
\(\dfrac{y}{3}=1,75\Rightarrow y=5,25\)
\(\dfrac{z}{5}=1,75\Rightarrow z=8,75\)


