a,\(\left(\frac{2^2}{5}\right)\)+\(5\frac{1}{2}\).(4,5-2,5)+\(\frac{2^3}{-4}\)
b,\(\left(-2^3\right)\)+\(\frac{1}{2}\):\(\frac{1}{8}\)-\(\sqrt{25}\)+|-64|
c,\(\frac{\sqrt{3^2+\sqrt{39}^2}}{\sqrt{91^2}-\sqrt{\left(-7^2\right)}}\)
d,\(\left(-2^2\right)+\sqrt{36}-\sqrt{9}+\sqrt{25}20.20\))
e,\(\sqrt{25}-3\sqrt{\frac{4}{9}}\)
h,\(\left(-3^2\right)\).\(\frac{1}{3}\)-\(\sqrt{49}\)+\(\left(5^3\right)\):\(\sqrt{25}\)
a) \(\left(\frac{2^2}{5}\right)+5\frac{1}{2}.\left(4,5-2,5\right)+\frac{2^3}{-4}\)
\(=\frac{4}{5}+\frac{11}{2}.2+\frac{-8}{4}\)
\(=\frac{4}{5}+11-2\)
\(=\frac{4}{5}+9\)
\(=\frac{49}{9}\)
b) \(\left(-2^3\right)+\frac{1}{2}:\frac{1}{8}-\sqrt{25}+\left|-64\right|\)
\(=-8+4-5+64\)
= 55
c) \(\frac{\sqrt{3^2+\sqrt{39}^2}}{\sqrt{91^2}-\sqrt{\left(-7\right)^2}}\)
\(=\frac{\sqrt{9+39}}{91-\sqrt{49}}\)
\(=\frac{\sqrt{48}}{91-7}\)
\(=\frac{4\sqrt{3}}{84}\)
\(=\frac{\sqrt{3}}{41}\)
d) Xem lại đề nhé em!
e) \(\sqrt{25}-3\sqrt{\frac{4}{9}}\)
\(=5-3.\frac{2}{3}\)
= 5 - 2
= 3
h) \(\left(-3^2\right).\frac{1}{3}-\sqrt{49}+\left(5^3\right):\sqrt{25}\)
\(=-9.\frac{1}{3}-7+125:5\)
\(=-3-7+25\)
= 15
