\(a,\Leftrightarrow4\left(x-2\right)=3\left(x+3\right)\left(x\ne-3\right)\\ \Leftrightarrow4x-8=3x+9\\ \Leftrightarrow x=17\left(tm\right)\\ b,\Leftrightarrow\dfrac{-1,04}{x}=\dfrac{18,72}{16,38}\\ \Leftrightarrow x=\dfrac{-1,04\cdot16,38}{18,72}=-0,91\)
a) ĐKXĐ: \(x\ne-3\)
\(\Leftrightarrow4x-8=3x+9\\ \Leftrightarrow x=17\)
b) \(\Leftrightarrow-1,04:x=\dfrac{8}{7}\\ \Leftrightarrow x=-\dfrac{91}{100}\)