Question

Tìm x:
a) x+\(\dfrac{1}{3}=\dfrac{3}{4}\) b)x-\(\dfrac{2}{5}=\dfrac{5}{7}\) c)-x-\(\dfrac{2}{3}=-\dfrac{6}{7}\) d)\(\dfrac{4}{7}-x=\dfrac{1}{3}\)

Answer 1

a) \(x+\dfrac{1}{3}=\dfrac{3}{4}\Leftrightarrow x=\dfrac{3}{4}-\dfrac{1}{3}\Leftrightarrow x=\dfrac{5}{12}\) vậy \(x=\dfrac{5}{12}\)

b) \(x-\dfrac{2}{5}=\dfrac{5}{7}\Leftrightarrow x=\dfrac{5}{7}+\dfrac{2}{5}\Leftrightarrow x=\dfrac{39}{35}\) vậy \(x=\dfrac{39}{35}\)

c) \(-x-\dfrac{2}{3}=\dfrac{-6}{7}\Leftrightarrow x=\dfrac{-2}{3}+\dfrac{6}{7}\Leftrightarrow x=\dfrac{4}{21}\) vậy \(x=\dfrac{4}{21}\)

d) \(\dfrac{4}{7}-x=\dfrac{1}{3}\Leftrightarrow x=\dfrac{4}{7}-\dfrac{1}{3}\Leftrightarrow x=\dfrac{5}{21}\) vậy \(x=\dfrac{5}{21}\)

Answer 2

a) x + \(\dfrac{1}{3}\) = \(\dfrac{3}{4}\)

x = \(\dfrac{3}{4}\) - \(\dfrac{1}{3}\)

x = \(\dfrac{5}{12}\)

Vậy x = \(\dfrac{5}{12}\)

b) x - \(\dfrac{2}{5}\) = \(\dfrac{5}{7}\)

x = \(\dfrac{5}{7}\) + \(\dfrac{2}{5}\)

x = \(\dfrac{39}{35}\)

Vậy x = \(\dfrac{39}{35}\)

c) -x - \(\dfrac{2}{3}\) = \(-\dfrac{6}{7}\)

- x = \(-\dfrac{6}{7}\) + \(\dfrac{2}{3}\)

- x = \(-\dfrac{4}{21}\)

⇒ x = \(\dfrac{4}{21}\)

Vậy x = \(\dfrac{4}{21}\)

d) \(\dfrac{4}{7}\) - x = \(\dfrac{1}{3}\)

x = \(\dfrac{4}{7}\) - \(\dfrac{1}{3}\)

x = \(\dfrac{5}{21}\)

Vậy x = \(\dfrac{5}{21}\)