\(A=\left(-7\right)+\left(-7\right)^2+....+\left(-7\right)^{2007}\)
\(A=-\left(7+7^2+...+7^{2007}\right)\)
\(7A=-\left(7^2+7^3+....+7^{2008}\right)\)
7A-A=6A= 72008- 7
=> A= \(\frac{7^{2008}-7}{6}\)
Mình làm vậy ko biết có đúng ko nữa
\(A=\left(-7\right)+\left(-7\right)^2+....+\left(-7\right)^{2007}\)
\(A=-\left(7+7^2+...+7^{2007}\right)\)
\(7A=-\left(7^2+7^3+....+7^{2008}\right)\)
7A-A=6A= 72008- 7
=> A= \(\frac{7^{2008}-7}{6}\)
Mình làm vậy ko biết có đúng ko nữa
1) Tìm \(n\in N\) để \(A=\left(x+5\right)\cdot\left(n+6\right)\) \(⋮\) \(6n\)
2)
a) Tính tổng \(A=\left(-7\right)+\left(-7\right)^2+.....+\left(-7\right)^{2006}+\left(-7\right)^{2007}\)
b) CMR: \(A⋮43\)
NẾU CÁC BẠN THẤY ĐỀ SAI THÌ NÓI MÌNH VS NHÉ
ai help me 1/ \(7^8.\left[-\frac{1}{7}\right]^8\)
2/ \(\left[\frac{4}{3}\right]^{10}.\left[\frac{-3}{4}\right]^{10}\)
3/ \(\left[-\frac{7}{2}\right]^{2006}.\left[-\frac{2}{7}\right]^{2006}\)
4/ \(\left[\frac{-5}{13}\right]^{2007}.\left[\frac{13}{5}\right]^{2006}\)
Tính tổng : S\(\left(\dfrac{-1}{7}\right)^0+\left(\dfrac{-1}{7}\right)^1+\left(\dfrac{-1}{7}\right)^2+....+\left(\dfrac{-1}{7}\right)^{2007}\)
Tính tổng : S = \(\left(\dfrac{-1}{7}\right)^0+\left(-\dfrac{1}{7}\right)^1+\left(-\dfrac{1}{7}\right)^2+...+\left(-\dfrac{1}{7}\right)^{2007}\)
Tính tổng: S= \(\left(-\frac{1}{7}\right)^0+\left(-\frac{1}{7}\right)^1+\left(-\frac{1}{7}\right)^2+...+\left(-\frac{1}{7}\right)^{2007}\)
Tính :
B = \(\left(-\dfrac{1}{7}\right)^0+\left(-\dfrac{1}{7}\right)^1+\left(-\dfrac{1}{7}\right)^2+....+\left(-\dfrac{1}{7}\right)^{2018}\)
Bài 1: Thực hiện phép tính: (Tính nhanh nếu có thể)
a) \(\frac{-1}{24}-\left[\frac{1}{4}-\left(\frac{1}{2}-\frac{7}{8}\right)\right]\)
b) \(\left(\frac{5}{7}-\frac{7}{5}\right)-\left[\frac{1}{2}-\left(-\frac{2}{7}-\frac{1}{10}\right)\right]\)
c) \(\left(-\frac{1}{2}\right)-\left(-\frac{3}{5}\right)+\left(-\frac{1}{9}\right)+\frac{1}{17}-\left(-\frac{2}{7}\right)+\frac{4}{35}-\frac{7}{18}\)
Mọi người ơi, giúp mk với!!!
Tìm x:
a)\(5\dfrac{4}{7}:\left\{x:1,3+8,4.\dfrac{6}{7}.\left[6-\dfrac{\left(2,3+5:6,25\right).7}{8.0,0125+6,9}\right]\right\}=1\dfrac{1}{14}\)
b)\(\left|3x-2\right|+\left|2x-1\right|=4\)
Tim x, biet:
a, \(\dfrac{x+1}{5}+\dfrac{x+1}{6}=\dfrac{x+1}{7}+\dfrac{x+1}{8}\)
b, \(\dfrac{x-1}{2009}+\dfrac{x-2}{2008}=\dfrac{x-3}{2007}+\dfrac{x-4}{2006}\)
c, \(\dfrac{3}{\left(x+2\right)\left(x+5\right)}+\dfrac{5}{\left(x+5\right)\left(x+10\right)}+\dfrac{7}{\left(x+10\right)\left(x+17\right)}\)\(=\dfrac{x}{\left(x+2\right)\left(x+17\right)}\)
d, \(\dfrac{2}{\left(x-1\right)\left(x-3\right)}+\dfrac{5}{\left(x-3\right)\left(x-8\right)}+\dfrac{12}{\left(x-8\right)\left(x-20\right)}-\dfrac{1}{x-20}=\dfrac{-3}{4}\)
Help me!!!!!!!!!!
Can gap lam. Ai lam duoc cau no thi lam nha. Cam on nhieu truoc!!!!!!!!!!!!