a,\(\text{ Xét }\dfrac{4n-5}{2n-1}=\dfrac{4n-2-3}{2n-1}=\dfrac{2\left(2n-1\right)-3}{2n-1}\)
\(=2-\dfrac{3}{2n-1}\)
\(\left(4n-5\right)⋮\left(2n-1\right)\) \(\Leftrightarrow2n-1\inƯ\left(3\right)=\left\{\pm1;\pm3\right\}\)
\(\Rightarrow n\in\left\{-1;0;1;2\right\}\)