aps dụng BĐTcauchy-schwarz dạng engel ta có
\(\dfrac{1}{a}+\dfrac{1}{b}+\dfrac{1}{c}\ge\dfrac{3^2}{a+b+c}\)
⇔ \(\dfrac{1}{a}+\dfrac{1}{b}+\dfrac{1}{c}\ge\dfrac{9}{1}\)
⇔ \(\dfrac{1}{a}+\dfrac{1}{b}+\dfrac{1}{c}\ge9\)(đpcm)
aps dụng BĐTcauchy-schwarz dạng engel ta có
\(\dfrac{1}{a}+\dfrac{1}{b}+\dfrac{1}{c}\ge\dfrac{3^2}{a+b+c}\)
⇔ \(\dfrac{1}{a}+\dfrac{1}{b}+\dfrac{1}{c}\ge\dfrac{9}{1}\)
⇔ \(\dfrac{1}{a}+\dfrac{1}{b}+\dfrac{1}{c}\ge9\)(đpcm)
cho 3 số dương a,b,c có tổng bằng 1.chứng minh rằng \(\dfrac{1}{a}+\dfrac{1}{b}+\dfrac{1}{c}\ge9\)
Chứng minh: \(\left(a+b+c\right)\left(\dfrac{1}{a}+\dfrac{1}{b}+\dfrac{1}{c}\right)\ge9\) với a, b, c>0.
Cho a+b+c=0 ; \(\dfrac{1}{a}\)+\(\dfrac{1}{b}\)+\(\dfrac{1}{c}\)=0. Chứng minh rằng: a2+b2+c2=1
Cho ba số dương a, b, c,. Chứng minh rằng: \(\dfrac{1}{a+b}+\dfrac{1}{b+c}+\dfrac{1}{c+a}>\dfrac{3}{a+b+c}\)
Cho a,b,c≠0 thỏa mán a+b+c=0.Chứng minh rằng:
\(\left(\dfrac{1}{a}+\dfrac{1}{b}+\dfrac{1}{c}\right)=\dfrac{1}{a^2}+\dfrac{1}{b^2}+\dfrac{1}{c^2}\)
Cho a,b,c là các số dương. Cm:
a. \(\left(a+b+c\right)\left(\dfrac{1}{a}+\dfrac{1}{b}+\dfrac{1}{c}\right)\ge9\)
b. \(\dfrac{a}{b+c}+\dfrac{b}{a+c}+\dfrac{c}{a+b}\ge\dfrac{3}{2}\)
1.Cho \(a,b,c,d\) là các số nguyên thỏa mãn \(a^3+b^3=2\left(c^3-d^3\right)\) . Chứng minh rằng a+b+c+d chia hết cho 3
2.Cho ba số dương a,b,c thỏa mãn abc=1. Chứng minh rằng \(\dfrac{1}{a^3\left(b+c\right)}+\dfrac{1}{b^3\left(c+a\right)}+\dfrac{1}{c^3\left(a+b\right)}\ge\dfrac{3}{2}\)
chứng minh rằng:\(\dfrac{a+b}{ab+c^2}+\dfrac{b+c}{bc+a^2}+\dfrac{c+a}{ac+b^2}\le\dfrac{1}{a}+\dfrac{1}{b}+\dfrac{1}{c}\)
cho \(\dfrac{a}{b+c}+\dfrac{b}{c+a}+\dfrac{c}{a+b}=1\) chứng minh rằng \(\dfrac{a^2}{b+c}+\dfrac{b^2}{c+a}+\dfrac{c^2}{a+b}=0\)