a)\(-\frac{3}{2}-2x+\frac{3}{4}=2\)
\(\Leftrightarrow-2x=2+\frac{3}{2}-\frac{3}{4}=\frac{11}{4}\)
\(\Leftrightarrow x=\frac{11}{4}:\left(-2\right)=-\frac{11}{8}\)
b , pt <=> \(\frac{x}{2}-\frac{3x}{5}+\frac{13}{5}=-\frac{7}{5}-\frac{7}{10}x\) <=> \(\frac{3}{5}x\) = -4 <=> x = \(\frac{-20}{3}\)
c , \(\frac{2}{3x}-\frac{3}{12}\) = \(\frac{4}{5}-\left(\frac{7}{x}-x\right)\) (ĐK : x khác 0 )
<=> \(\frac{23}{3x}\) - x =\(\frac{21}{20}\) <=>\(-3x^2-\frac{21}{20}.3x+23=0\Leftrightarrow\left[{}\begin{matrix}x=\\x=\end{matrix}\right.\)...
a) \(-\frac{3}{2}-2x+\frac{3}{4}=2\)
⇔ \(-2x=2+\frac{3}{2}-\frac{3}{4}\)
⇔ \(-2x=\frac{11}{4}\)
⇔ \(x=\frac{11}{4}:\left(-2\right)\)
=> \(x=-\frac{11}{8}\)
Vậy \(x=-\frac{11}{8}\).
Mình chỉ làm câu a) thôi nhé.
Chúc bạn học tốt!