Question

a) (-2/3)^8 + (-2/3)^8

giúp e vs ạ :<

Answer 1

\(a,\left(-\dfrac{2}{3}\right)^8+\left(-\dfrac{2}{3}\right)^8=2\left(-\dfrac{2}{3}\right)^8=2\cdot\dfrac{\left(-2\right)^8}{3^8}=\dfrac{2\cdot2^8}{3^8}=\dfrac{2^9}{3^8}=\dfrac{512}{6561}\)

Answer 2

\(\left(-\dfrac{2}{3}\right)^8+\left(-\dfrac{2}{3}\right)^8\)

\(=\left(\dfrac{2}{3}\right)^8+\left(\dfrac{2}{3}\right)^8\)

\(=2\left(\dfrac{2}{3}\right)^8\)

\(=2.\dfrac{256}{6561}\)

\(=\dfrac{512}{6561}\)