a. 2x = 8 ; b. 5x = 25 ; c. 3x : 35 = 9 d. \(\dfrac{16}{2^x}=2\) ; e. 8x : 2x = 4 ; f. 2x . 3x = 36 ; g. \(\dfrac{\left(-3\right)^n}{81}=-27\)
2x = 23 5x = 52 3x : 35 = 32 \(\dfrac{2^4}{2^x}=1\) ( 23)x : 2x = 22 6x = 62 \(\dfrac{\left(-3\right)^n}{\left(-3\right)^4}=\left(-3\right)^3\)
x = 3 x = 3 3x = 32 . 35 \(2^{4-x}=2^1\) 23x : 2x = 22 x = 2 \(\left(-3\right)^n=\left(-3\right)^3.\left(-3\right)^4\)
3x = 37 \(\Rightarrow4-x=1\) 23x - x = 22 \(\left(-3\right)^n=\left(-7\right)^7\)
=>X = 7 x = 4 - 1 22x = 22 => n = 7
x = 3 2x = 2
x = 2 : 2
x = 1