\(\Leftrightarrow4\left(sin^2x+cos^2x\right)^2-8sin^2x.cos^2x+\sqrt{3}sin4x=2\)
\(\Leftrightarrow4-2sin^22x+\sqrt{3}sin4x=2\)
\(\Leftrightarrow cos4x+\sqrt{3}sin4x=-1\)
\(\Leftrightarrow\frac{1}{2}cos4x+\frac{\sqrt{3}}{2}sin4x=-\frac{1}{2}\)
\(\Leftrightarrow cos\left(4x-\frac{\pi}{3}\right)=-\frac{1}{2}\)
\(\Leftrightarrow...\)