\(\Rightarrow\left(2x-5\right)^5=9^5\\ \Rightarrow2x-5=9\\ \Rightarrow x=7\)
\(\left(2x-5\right)^5=3^{10}\)
\(\Leftrightarrow2x-5=9\)
hay x=7
(2x - 5)5 = 310
<=> (2x - 5)5 = 95
<=> \(\sqrt[5]{\left(2x-5\right)^5}=\sqrt[5]{9^5}\)
<=> 2x - 5 = 9
<=> 2x = 9 + 5
<=> 2x = 14
<=> x = 7
Giải:
\(\left(2x-5\right)^5=3^{10}\)
= \(\left(2x-5\right)^5=9^5\)
\(\Rightarrow\) \(2x-5=9\)
Vậy \(x=7\)
Hok tốt