a) x+5+2.x=17
x.1+2x=17-5
x.(2+1)=12
x.3=12
x=12:3
x=4
vay x = 4
c) (3-x).(x+5)=0
\(\Rightarrow\left[{}\begin{matrix}3-x=0\\x+5=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=3-0\\x=0-5\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=3\\x=-5\end{matrix}\right.\)
vay x \(\in\left\{3:-5\right\}\)
d) (2.x+2).(x-19)=0
\(\Rightarrow\left[{}\begin{matrix}2x+2=0\\x-19=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}2x=0-2\\x=0+19\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}2x=-2\\x=19\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-2:2\\x=19\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-1\\x=19\end{matrix}\right.\)
vay x \(\in\left\{-1;19\right\}\)
e) (x+2)3=(-125)
x+2=-125:3( loai )
vay x ko co gia tri nao thoa man
f) |x-3|=4
\(\Rightarrow\left[{}\begin{matrix}x-3=4\\x-3=-4\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=4+3\\x=-4+3\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=7\\x=-1\end{matrix}\right.\)
vay x\(\in\left\{7;-1\right\}\)
g) 2.|7-x|=16
\(\)/7-x/=16:2
/7-x/=8
\(\Rightarrow\left[{}\begin{matrix}7-x=-8\\7-x=8\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-8+7\\x=8+7\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-1\\x=15\end{matrix}\right.\)
vay \(x\in\left\{-1;15\right\}\)
h) 12-2.|x-10|=(-18)
2/x-10/=-18+12
2/x-10/=-6
/x-10/=-6:2
/x-10/=-3
\(\Rightarrow\left[{}\begin{matrix}x-10=3\\x-10=-3\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=3-10\\x=-3+10\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-7\\x=7\end{matrix}\right.\)
vay \(x\in\left\{-7;7\right\}\)
sorry ban vi mik ko lam dc phan b mong ban thong cam
mik xin thay Trần Ngoc an làm câu b
x-11=2x+4
=> x-11-4 = 2x
=> x-15 = 2x
=> x-15 = x+x
=> x-15 = x - (-x)
=> 15= -x
=> x = -15
@Vũ Ngọc Diệp ơi, mk lm câu b nhưng ko giống cách của bn @nguyễn huy hoàng (tag hộ) nhé!!!
b) x-11 =2.x+4
-11-4= 2x - x
-11+(-4)= x
-15 = x
=> x = -15
a, x+5 + 2x = 17
3x + 5 = 17
3x = 12
x = 4 ( thỏa mãn )
b, x - 11 = 2x + 4
x - 2x = 4 + 11
-x = 15
x = -15 ( thỏa mãn )
c, (3 - x)(x + 5) = 0
\(\Rightarrow\left[{}\begin{matrix}3-x=0\\x+5=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\left(thỏamãn\right)\\x=-5\left(thỏamãn\right)\end{matrix}\right.\)
d,(2x + 2)(x - 19) = 0
\(\Rightarrow\left[{}\begin{matrix}2x+2=0\\x-19=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-1\left(thỏamãn\right)\\x=19\left(thỏamãn\right)\end{matrix}\right.\)
e, (x + 2)3 = -125
x +2 = \(\frac{-125}{3}\)
x = \(\frac{-131}{3}\left(loại\right)\)
f, |x - 3| = 4
TH1: x - 3 = 4
x = 7 (thỏa mãn)
TH2: x - 3 = -4
x = -1 (thỏa mãn)
g, 2.|7 - x| = 16
|7 - x| = 8
TH1: 7 - x = 8
x = -1 (thỏa mãn)
TH2: 7 - x = -8
x = 15 (thỏa mãn)
h, 12 - 2.|x - 10| = -18
-2.|x - 10| = -30
|x - 10| = 15
TH1: x - 10 = 15
x = 25 (thỏa mãn)
TH2: x - 10 = -15
x = -5 (thỏa mãn)
Chúc bạn học tốt !