Gọi H là trung điểm AB. Ta có:
\(E_A=E_B=\frac{kq}{AM^2}=\frac{kq}{\sqrt{a^2+h^2}}\)
\(E_M=\sqrt{E_A^2+E_B^2+2E_AE_B.cos\left(AMB\right)}\)
\(=\sqrt{2E_A^2+2E_A^2.\left(2cos^2\alpha-1\right)}\)
\(=\sqrt{4E_A^2.cos^2\alpha}=2E_A.cos\alpha\)
\(=\frac{2kq}{a\sqrt{a^2+h^2}}\)
Dễ thấy\(E_M\) đạt gtln khi \(h=0\Leftrightarrow E_M=\frac{2kq}{a^2}\)