1)tìm x biết:
a)(x-2)^2=1
b)(2x-1)^3=-8
c)(x+1/2)^2=1/16
d)(x-2)^3=-27
e(2x-3)^2=25
g)3^x-1=1/243
h)2^x+2^x+3=144
k)81^-2x*27^x=95
1)tìm x biết:
a)(x-2)^2=1
b)(2x-1)^3=-8
c)(x+1/2)^2=1/16
d)(x-2)^3=-27
e(2x-3)^2=25
g)3^x-1=1/243
h)2^x+2^x+3=144
k)81^-2x*27^x=95
Tìm x
a) x-6/7 + x-7/8 + x-8/9 = x-9/10 + x-10/11+x-11/12
b) x+32/11 + x+23/12 = x+38/13 + x+27/14
c) | x-2| = 13
d) 3|x-2| + |4x-8| = |-2| - |1/3|
e) |3x-2|+5^-1 = 3 + | x- (2/3) |
f) | x+2 | + | x-2 | = 3
g) (2x-1)^2 - 5 = 20
i) (x+2)^2 = 1/2 - 1/3
k) (x-1)^3 = (x-1)
m) (x-1)^x+2 = (x-1)^2
n) (x+3)^y+1 = (2x-1)^y+1 vs y là 1 số tự nhiên .
a)x2+x=0
c)(2x+1)2=25
d)(2x-3)2=36
e)5x+2=625
f)(x-1)x+2=(x-1)x+4
f(x) = x2-2x2+3x+1
g(x)=x3+x+1
h(x)=2x2-1
Tìm x sao cho f(x) - g(x) + h(x) =0
Cho các đa thức :
F(x)=\(-x^4-3x^3+x^2-2x+5\)
G(x)=\(6^4+x^3-2x^2-3x-3\)
H(x)=\(-5x^4+2x^3+2x^2+9x+3\)
a)Tính F(x)+G(x)+H(x) và 2.F(x) - [G(x)+H(x)]
b)Tính giá trị F(-1),G(\(\dfrac{-1}{2}\));H(2)
c)Chứng minh rằng F(x)+G(x)+H(x) >0
d)Tìm x để giá trị của F(x)+G(x)+H(x) bằng 1
bai 1: cho cac da thuc
f(x)= x^5-3x^2+7x^4-x^5+2x^2-9x^3+x^2-1/4x+2x-3
g(x)=5x^4-x^5+1/2x^4+x^5+x^2-4x^4-2x^3+3x^2+x^3-1/4
a, thu gon va sap xep cac da thuc tren theo luy thua giam dancua ien
b,tinh f(1);f(-1); g(1); g(-1)
c,tinh f(x)+g(x);f(x)-g(x)
Tìm x biết:
a) (2x+1)^5= (2x+1)
b) |2-5x|=|x+1|
c) |x-3|+(x^2 -9)^2=0
d) |4x+1| -2x+3=5
1. Tìm x:
a. |x| = 5,6 b. |x-3,5| = 5 c.|x+\(\dfrac{3}{4}\)| - \(\dfrac{1}{2}\)= 0 d. |4x| -|-13,5| = |\(\dfrac{9}{4}\)|
e. (x-1)3 = 27 f. (2x-3)2=36 g. 5x + 2= 625 h. (2x -1) 3 = -8
i.* \(\dfrac{1}{4}\).\(\dfrac{2}{6}.\dfrac{3}{8}.\dfrac{4}{10}.\dfrac{5}{12}...\dfrac{30}{62}.\dfrac{31}{64}=2^x\)
Cho f(x) = 2x3 - 3x + x2 - 5x - 2x2 + 1
g(x)= 3x2 - 2x - x3 +2
Tính : f(x) + g(x)
f(x) - g(x)