Ta có: \(\left|x-2\right|-\left|2x+3\right|-x=-2\)
=>|x-2|-|2x+3|=x-2(1)
Trường hợp 1: x<-3/2
(1) trở thành 2-x-(-2x-3)=x-2
=>2-x+2x+3=x-2
=>x+5=x-2(loại)
Trường hợp 2: -3/2<=x<2
(1) trở thành 2-x-2x-3=x-2
=>-3x-1=x-2
=>-4x=-1
hay x=1/4(nhận)
Trường hợp 3: x>=2
(1) trở thành x-2-2x-3=x-2
=>-2x-3=0
=>-2x=3
hay x=-3/2(loại)
tím x biết: \(\left|2x+3\right|+\left|2x-1\right|=\dfrac{8}{3\left(x+1\right)^2+2}\)
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Thanks mn nhiều......
4, tìm x biết;
a, \(\left|x-1\right|+\left|x-3\right|=4\)
b. \(\left|2x-1\right|+\left|x+2\right|=3\)
a)\(\frac{-3}{2}-2x+\frac{3}{4}=-2\)
b)\(\left(\frac{-2}{3}x-\frac{3}{5}\right)\left(\frac{3}{-2}-\frac{10}{3}\right)=\frac{2}{5}\)
c)\(\frac{x}{2}-\left(\frac{3x}{5}-\frac{13}{5}\right)=-\left(\frac{7}{5}+\frac{7}{10}.x\right)\)
d)\(\frac{2x-3}{3}+\frac{-3}{2}=\frac{5-3x}{6}-\frac{1}{3}\)
e)\(\frac{2}{3x}-\frac{3}{12}=\frac{4}{5}-\left(\frac{7}{x}2\right)\)
k)\(\frac{13}{x-1}+\frac{5}{2x-2}-\frac{6}{3x-3}\)
m)\(\left(\frac{3}{2}-\frac{2}{-5}\right):x-\frac{1}{2}=\frac{3}{2}\)
n)\(\left(\frac{3}{2}-\frac{5}{11}-\frac{3}{13}\right)\left(2x-2\right)=\left(\frac{-3}{4}+\frac{5}{22}+\frac{3}{26}\right)\)
Giải giúp mk
mk đang cần ghấp trong hôm nay
cám ơn mọi người
Tìm x, biết:
a) \(\left(x-\frac{-7}{8}\right)+2,3=3,24\) ; b) \(x.\left(4,6+\frac{3}{5}\right)=7,2-8,15\) ; c) |2x-3|+3=16 ; d) \(42+\frac{3}{7}.\left|3x-1\right|=12\)
e) \(\left(x-\frac{1}{2}\right).\left(1+5x\right)=0\) ; f) |2x-1|=|x+2| ; g) \(2.3^x.3^2=18\left(x\in N\right)\) ; h) \(\frac{x+2}{5}=\frac{2-3x}{3}\)
tìm x, biết
a) \(\left|x+2\right|+\left|x-3\right|=7\)
b) \(\left|x+2\right|-6x=1\)
c) \(\left|2x+1\right|+\left|x+8\right|=4x\)
d) \(x+\left|x+2017\right|=-2017\)
1) \(\left|3x+2\right|=\left|x+1\right|\)
2) \(\left|\left(x+2\right)\times x\right|=\left|x+2\right|\)
3) \(\left|2x+3\right|=x+1\)
4) \(\left|4x+5\right|+3.x=7\)
2, Tìm x biết:
a, \(\left|2x-3\right|=\left|3x+4\right|\)
b, \(\left|5-3x\right|=\left|x-1\right|\)
a)\(\left(x-\frac{2}{3}\right)\). \(\left(x+\frac{1}{4}\right)\)= 0
b) \(\left(x-\frac{2}{3}\right)\). \(\left(2x-\frac{3}{4}\right)\) = \(\left(3x+\frac{1}{2}\right)\). \(\left(x+\frac{2}{3}\right)\)
Bài 2: Tìm x,y,z biết:
a) \(|\left(-1.1\right)^2\cdot5-1.1\cdot15.5|\cdot x-2=-2^3\cdot\left(-\dfrac{1}{2}\right)^3-\dfrac{1}{2}\)
b) \(3^{x+2}+4\cdot3^{x+1}+3^{x-1}=6^6\)
c) \(3+2^{x-1}=24-[4^2-\left(2^2-1\right)]\)
d) \(x:\left(-3\right)=y:4=z:5\) và \(-2x+7y-3z=171\)
e) \(\dfrac{x-2}{4}=\dfrac{-16}{2-x}\)
g) \(3x+x^2=0\)
h) \(\left(x-\dfrac{1}{2}\right)^5=\dfrac{1}{243}\)
i) \(\dfrac{4+x}{7+y}=\dfrac{4}{7}\) và \(x+y=22\)
Mn giúp e với nha... cảm ơn mn nhiều lắm ạ!!!
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